add lab 07 doc comments

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SowinskiBraeden committed 2026-03-11 19:20:21 -07:00
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(** A lazy infinite stream containing values of type ['a]. *)
type 'a lazystream = Cons of 'a * 'a lazystream Lazy.t type 'a lazystream = Cons of 'a * 'a lazystream Lazy.t
(** [from n] creates an infinite lazy stream starting at [n]
* and increasing by [1.] for each subsequent element.
*)
let rec from n = Cons (n, lazy (from (n +. 1.))) let rec from n = Cons (n, lazy (from (n +. 1.)))
(** [take n s] returns a list containing the first [n] elements
* of lazy stream [s].
* If [n <= 0], it returns the empty list.
*)
let rec take n (Cons (h, t)) = let rec take n (Cons (h, t)) =
if n <= 0 then [] if n <= 0 then []
else h :: take (n - 1) (Lazy.force t) else h :: take (n - 1) (Lazy.force t)
(** [map f s] returns a new lazy stream where function [f]
* is applied to every element of stream [s].
*)
let rec map f (Cons (h, t)) = let rec map f (Cons (h, t)) =
Cons (f h, lazy (map f (Lazy.force t))) Cons (f h, lazy (map f (Lazy.force t)))
(** [fact n] computes the factorial of [n].
* This function assumes [n] is a non-negative floating-point integer value.
*)
let fact n = let fact n =
let rec fact' acc i = let rec fact' acc i =
if i = 0. then acc if i = 0. then acc
@@ -16,13 +30,25 @@ let fact n =
in in
fact' 1. n;; fact' 1. n;;
(** [fold_left f acc l] applies function [f] to each element of list [l]
* from left to right, carrying an accumulator [acc].
* The function [f] takes the current accumulator and element
* and produces a new accumulator.
*)
let rec fold_left f acc l = let rec fold_left f acc l =
match l with match l with
| [] -> acc | [] -> acc
| a :: l' -> fold_left f (f acc a) l';; | a :: l' -> fold_left f (f acc a) l';;
(** [exp_terms x] returns an infinite lazy stream of terms in the
* Taylor series expansion of [e^x], where each term is
* [(x ** n) /. fact n] for [n = 0., 1., 2., ...].
*)
let exp_terms x = map (fun n -> (x**n) /. (fact n)) @@ from 0.;; let exp_terms x = map (fun n -> (x**n) /. (fact n)) @@ from 0.;;
(** [exp n x] approximates [e^x] by summing the first [n]
* terms of the Taylor series expansion for [e^x].
*)
let exp n x = fold_left (+.) 0. (take n @@ exp_terms x);; let exp n x = fold_left (+.) 0. (take n @@ exp_terms x);;
exp 20 1.1;; exp 20 1.1;;
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(** An infinite stream containing values of type ['a],
* where the tail is produced by a thunk.
*)
type 'a infstream = Cons of 'a * (unit -> 'a infstream) type 'a infstream = Cons of 'a * (unit -> 'a infstream)
(** [take n s] returns a list containing the first [n] elements
* of infinite stream [s].
* If [n <= 0], it returns the empty list.
*)
let rec take n (Cons (h, t)) = let rec take n (Cons (h, t)) =
if n <= 0 then [] if n <= 0 then []
else h :: take (n - 1) (t ()) else h :: take (n - 1) (t ())
(** [from n] creates an infinite stream of integers starting at [n]
* and increasing by [1] for each subsequent element.
*)
let rec from n = Cons (n, fun () -> from (n + 1)) let rec from n = Cons (n, fun () -> from (n + 1))
(** [filter f s] returns a new infinite stream containing only
* the elements of stream [s] that satisfy predicate [f].
*)
let rec filter f (Cons (h, t)) = let rec filter f (Cons (h, t)) =
if f h then Cons (h, fun () -> filter f (t ())) if f h then Cons (h, fun () -> filter f (t ()))
else filter f (t ()) else filter f (t ())
(** [primes] is an infinite stream of prime numbers generated
* using the sieve of Eratosthenes.
*)
let primes = let primes =
let rec sieve (Cons (h, t)) = let rec sieve (Cons (h, t)) =
Cons (h, fun () -> Cons (h, fun () ->